x^2+12x-1200=0

Solution for x^2+12x-1200=0 equation:

x^2+12x-1200=0

a = 1; b = 12; c = -1200;
Δ = b2-4ac
Δ = 122-4·1·(-1200)
Δ = 4944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4944}=\sqrt{16*309}=\sqrt{16}*\sqrt{309}=4\sqrt{309}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{309}}{2*1}=\frac{-12-4\sqrt{309}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{309}}{2*1}=\frac{-12+4\sqrt{309}}{2}
$